The figure shows a square DEHJ and a rectangle EFGH. ∠FJH = 40°.
- Find ∠ELJ.
- Find ∠DKF.
(a)
∠ELJ
= 40° + 90°
= 130° (Exterior angle of a triangle)
(b)
∠DHJ = 45°
∠HKJ
= 180° - 40° - 45°
= 95° (Angles sum of triangle)
∠DKF
= ∠HKJ
= 95° (Vertically opposite angles)
Answer(s): (a) 130°; (b) 95°