The figure shows a square CDGH and a rectangle DEFG. ∠EHG = 41°.
- Find ∠DKH.
- Find ∠CJE.
(a)
∠DKH
= 41° + 90°
= 131° (Exterior angle of a triangle)
(b)
∠CGH = 45°
∠GJH
= 180° - 41° - 45°
= 94° (Angles sum of triangle)
∠CJE
= ∠GJH
= 94° (Vertically opposite angles)
Answer(s): (a) 131°; (b) 94°