The figure shows a square BCFG and a rectangle CDEF. ∠DGF = 36°.
- Find ∠CJG.
- Find ∠BHD.
(a)
∠CJG
= 36° + 90°
= 126° (Exterior angle of a triangle)
(b)
∠BFG = 45°
∠FHG
= 180° - 36° - 45°
= 99° (Angles sum of triangle)
∠BHD
= ∠FHG
= 99° (Vertically opposite angles)
Answer(s): (a) 126°; (b) 99°