The figure shows a square HJMN and a rectangle JKLM. ∠KNM = 45°.
- Find ∠JQN.
- Find ∠HPK.
(a)
∠JQN
= 45° + 90°
= 135° (Exterior angle of a triangle)
(b)
∠HMN = 45°
∠MPN
= 180° - 45° - 45°
= 90° (Angles sum of triangle)
∠HPK
= ∠MPN
= 90° (Vertically opposite angles)
Answer(s): (a) 135°; (b) 90°