The figure shows a square JKNP and a rectangle KLMN. ∠LPN = 36°.
- Find ∠KRP.
- Find ∠JQL.
(a)
∠KRP
= 36° + 90°
= 126° (Exterior angle of a triangle)
(b)
∠JNP = 45°
∠NQP
= 180° - 36° - 45°
= 99° (Angles sum of triangle)
∠JQL
= ∠NQP
= 99° (Vertically opposite angles)
Answer(s): (a) 126°; (b) 99°