The figure shows a square BCFG and a rectangle CDEF. ∠DGF = 45°.
- Find ∠CJG.
- Find ∠BHD.
(a)
∠CJG
= 45° + 90°
= 135° (Exterior angle of a triangle)
(b)
∠BFG = 45°
∠FHG
= 180° - 45° - 45°
= 90° (Angles sum of triangle)
∠BHD
= ∠FHG
= 90° (Vertically opposite angles)
Answer(s): (a) 135°; (b) 90°