The figure shows a square HJMN and a rectangle JKLM. ∠KNM = 39°.
- Find ∠JQN.
- Find ∠HPK.
(a)
∠JQN
= 39° + 90°
= 129° (Exterior angle of a triangle)
(b)
∠HMN = 45°
∠MPN
= 180° - 39° - 45°
= 96° (Angles sum of triangle)
∠HPK
= ∠MPN
= 96° (Vertically opposite angles)
Answer(s): (a) 129°; (b) 96°