The table shows the types of coins collected by 4 children.
- Who collected the most number of coins? Choose the letter. (Eg A)
- Bobby wanted to give 12 of his Peru coins to the other 3 children. If each child received the same number of coins from Bobby, how many coins did each of them receive?
(a)
Number of coins collected
(A) Mary → 130 + 99 = 229
(B) Luis → 37 + 144 = 181
(C) Penelope → 104 + 17 = 121
(D) Bobby → 66 + 145 = 211
Mary (A) has the most coins.
(b)
Number of Peru coins that Bobby had = 2 u
2 u = 66
1 u = 66 ÷ 3 = 33
Number of coins that each child received
= 33 ÷ 3
= 11
Answer(s): (a) A; (b) 11