The table shows the types of coins collected by 4 children.
- Who collected the most number of coins? Choose the letter. (Eg A)
- Jane wanted to give 13 of her China coins to the other 3 children. If each child received the same number of coins from Jane, how many coins did each of them receive?
(a)
Number of coins collected
(A) Opal → 102 + 46 = 148
(B) Daniel → 128 + 41 = 169
(C) Jane → 86 + 153 = 239
(D) Reggie → 19 + 166 = 185
Jane (C) had the most coins.
(b)
Number of China coins that Jane had = 3 u
3 u = 153
1 u = 153 ÷ 3 = 51
Number of coins that each child received
= 51 ÷ 3
= 17
Answer(s): (a) C; (b) 17