In the figure, PQRS and QUVW are two rhombuses. If ∠UVW = 121° and ∠PSR = 91°, calculate
- ∠VUW
- ∠VRQ
- ∠WXR
(a)
∠VUW
= (180° - 121°) ÷ 2
= 29.5° (Isosceles triangle)
(b)
∠VRQ = ∠PSR = 91° (Corresponding angles)
(c)
∠WXR
= 91° - 29.5°
= 61.5° (Exterior angle of a triangle)
Answer(s): (a) 29.5°; (b) 91°; (c) 61.5°