In the figure, MNPQ and NSTU are two rhombuses. If ∠STU = 112° and ∠MQP = 96°, calculate
- ∠TSU
- ∠TPN
- ∠UVP
(a)
∠TSU
= (180° - 112°) ÷ 2
= 34° (Isosceles triangle)
(b)
∠TPN = ∠MQP = 96° (Corresponding angles)
(c)
∠UVP
= 96° - 34°
= 62° (Exterior angle of a triangle)
Answer(s): (a) 34°; (b) 96°; (c) 62°