In the figure, QRST and RVWX are two rhombuses. If ∠VWX = 106° and ∠QTS = 102°, calculate
- ∠WVX
- ∠WSR
- ∠XYS
(a)
∠WVX
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
(b)
∠WSR = ∠QTS = 102° (Corresponding angles)
(c)
∠XYS
= 102° - 37°
= 65° (Exterior angle of a triangle)
Answer(s): (a) 37°; (b) 102°; (c) 65°