In the figure, GHJK and HMNP are two rhombuses. If ∠MNP = 122° and ∠GKJ = 102°, calculate
- ∠NMP
- ∠NJH
- ∠PQJ
(a)
∠NMP
= (180° - 122°) ÷ 2
= 29° (Isosceles triangle)
(b)
∠NJH = ∠GKJ = 102° (Corresponding angles)
(c)
∠PQJ
= 102° - 29°
= 73° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 102°; (c) 73°