In the figure, ABCD and BFGH are two rhombuses. If ∠FGH = 118° and ∠ADC = 93°, calculate
- ∠GFH
- ∠GCB
- ∠HJC
(a)
∠GFH
= (180° - 118°) ÷ 2
= 31° (Isosceles triangle)
(b)
∠GCB = ∠ADC = 93° (Corresponding angles)
(c)
∠HJC
= 93° - 31°
= 62° (Exterior angle of a triangle)
Answer(s): (a) 31°; (b) 93°; (c) 62°