In the figure, QRST and RVWX are two rhombuses. If ∠VWX = 122° and ∠QTS = 100°, calculate
- ∠WVX
- ∠WSR
- ∠XYS
(a)
∠WVX
= (180° - 122°) ÷ 2
= 29° (Isosceles triangle)
(b)
∠WSR = ∠QTS = 100° (Corresponding angles)
(c)
∠XYS
= 100° - 29°
= 71° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 100°; (c) 71°