In the figure, JKLM and KPQR are two rhombuses. If ∠PQR = 115° and ∠JML = 101°, calculate
- ∠QPR
- ∠QLK
- ∠RSL
(a)
∠QPR
= (180° - 115°) ÷ 2
= 32.5° (Isosceles triangle)
(b)
∠QLK = ∠JML = 101° (Corresponding angles)
(c)
∠RSL
= 101° - 32.5°
= 68.5° (Exterior angle of a triangle)
Answer(s): (a) 32.5°; (b) 101°; (c) 68.5°