In the figure, MNPQ and NSTU are two rhombuses. If ∠STU = 123° and ∠MQP = 101°, calculate
- ∠TSU
- ∠TPN
- ∠UVP
(a)
∠TSU
= (180° - 123°) ÷ 2
= 28.5° (Isosceles triangle)
(b)
∠TPN = ∠MQP = 101° (Corresponding angles)
(c)
∠UVP
= 101° - 28.5°
= 72.5° (Exterior angle of a triangle)
Answer(s): (a) 28.5°; (b) 101°; (c) 72.5°