In the figure, JKLM and KPQR are two rhombuses. If ∠PQR = 124° and ∠JML = 93°, calculate
- ∠QPR
- ∠QLK
- ∠RSL
(a)
∠QPR
= (180° - 124°) ÷ 2
= 28° (Isosceles triangle)
(b)
∠QLK = ∠JML = 93° (Corresponding angles)
(c)
∠RSL
= 93° - 28°
= 65° (Exterior angle of a triangle)
Answer(s): (a) 28°; (b) 93°; (c) 65°