In the figure, JKLM and KPQR are two rhombuses. If ∠PQR = 105° and ∠JML = 99°, calculate
- ∠QPR
- ∠QLK
- ∠RSL
(a)
∠QPR
= (180° - 105°) ÷ 2
= 37.5° (Isosceles triangle)
(b)
∠QLK = ∠JML = 99° (Corresponding angles)
(c)
∠RSL
= 99° - 37.5°
= 61.5° (Exterior angle of a triangle)
Answer(s): (a) 37.5°; (b) 99°; (c) 61.5°