In the figure, GHJK and HMNP are two rhombuses. If ∠MNP = 115° and ∠GKJ = 91°, calculate
- ∠NMP
- ∠NJH
- ∠PQJ
(a)
∠NMP
= (180° - 115°) ÷ 2
= 32.5° (Isosceles triangle)
(b)
∠NJH = ∠GKJ = 91° (Corresponding angles)
(c)
∠PQJ
= 91° - 32.5°
= 58.5° (Exterior angle of a triangle)
Answer(s): (a) 32.5°; (b) 91°; (c) 58.5°