In the figure, GHJK and HMNP are two rhombuses. If ∠MNP = 118° and ∠GKJ = 97°, calculate
- ∠NMP
- ∠NJH
- ∠PQJ
(a)
∠NMP
= (180° - 118°) ÷ 2
= 31° (Isosceles triangle)
(b)
∠NJH = ∠GKJ = 97° (Corresponding angles)
(c)
∠PQJ
= 97° - 31°
= 66° (Exterior angle of a triangle)
Answer(s): (a) 31°; (b) 97°; (c) 66°