In the figure, FGHJ and GLMN are two rhombuses. If ∠LMN = 108° and ∠FJH = 93°, calculate
- ∠MLN
- ∠MHG
- ∠NPH
(a)
∠MLN
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
(b)
∠MHG = ∠FJH = 93° (Corresponding angles)
(c)
∠NPH
= 93° - 36°
= 57° (Exterior angle of a triangle)
Answer(s): (a) 36°; (b) 93°; (c) 57°