In the figure, NPQR and PTUV are two rhombuses. If ∠TUV = 116° and ∠NRQ = 92°, calculate
- ∠UTV
- ∠UQP
- ∠VWQ
(a)
∠UTV
= (180° - 116°) ÷ 2
= 32° (Isosceles triangle)
(b)
∠UQP = ∠NRQ = 92° (Corresponding angles)
(c)
∠VWQ
= 92° - 32°
= 60° (Exterior angle of a triangle)
Answer(s): (a) 32°; (b) 92°; (c) 60°