In the figure, QRST and RVWX are two rhombuses. If ∠VWX = 109° and ∠QTS = 96°, calculate
- ∠WVX
- ∠WSR
- ∠XYS
(a)
∠WVX
= (180° - 109°) ÷ 2
= 35.5° (Isosceles triangle)
(b)
∠WSR = ∠QTS = 96° (Corresponding angles)
(c)
∠XYS
= 96° - 35.5°
= 60.5° (Exterior angle of a triangle)
Answer(s): (a) 35.5°; (b) 96°; (c) 60.5°