In the figure, PQRS and QUVW are two rhombuses. If ∠UVW = 112° and ∠PSR = 95°, calculate
- ∠VUW
- ∠VRQ
- ∠WXR
(a)
∠VUW
= (180° - 112°) ÷ 2
= 34° (Isosceles triangle)
(b)
∠VRQ = ∠PSR = 95° (Corresponding angles)
(c)
∠WXR
= 95° - 34°
= 61° (Exterior angle of a triangle)
Answer(s): (a) 34°; (b) 95°; (c) 61°