In the figure, NPQR and PTUV are two rhombuses. If ∠TUV = 111° and ∠NRQ = 98°, calculate
- ∠UTV
- ∠UQP
- ∠VWQ
(a)
∠UTV
= (180° - 111°) ÷ 2
= 34.5° (Isosceles triangle)
(b)
∠UQP = ∠NRQ = 98° (Corresponding angles)
(c)
∠VWQ
= 98° - 34.5°
= 63.5° (Exterior angle of a triangle)
Answer(s): (a) 34.5°; (b) 98°; (c) 63.5°