In the figure, MNPQ and NSTU are two rhombuses. If ∠STU = 124° and ∠MQP = 100°, calculate
- ∠TSU
- ∠TPN
- ∠UVP
(a)
∠TSU
= (180° - 124°) ÷ 2
= 28° (Isosceles triangle)
(b)
∠TPN = ∠MQP = 100° (Corresponding angles)
(c)
∠UVP
= 100° - 28°
= 72° (Exterior angle of a triangle)
Answer(s): (a) 28°; (b) 100°; (c) 72°