In the figure, NPQR and PTUV are two rhombuses. If ∠TUV = 105° and ∠NRQ = 96°, calculate
- ∠UTV
- ∠UQP
- ∠VWQ
(a)
∠UTV
= (180° - 105°) ÷ 2
= 37.5° (Isosceles triangle)
(b)
∠UQP = ∠NRQ = 96° (Corresponding angles)
(c)
∠VWQ
= 96° - 37.5°
= 58.5° (Exterior angle of a triangle)
Answer(s): (a) 37.5°; (b) 96°; (c) 58.5°