In the figure, ABCD and BFGH are two rhombuses. If ∠FGH = 106° and ∠ADC = 97°, calculate
- ∠GFH
- ∠GCB
- ∠HJC
(a)
∠GFH
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
(b)
∠GCB = ∠ADC = 97° (Corresponding angles)
(c)
∠HJC
= 97° - 37°
= 60° (Exterior angle of a triangle)
Answer(s): (a) 37°; (b) 97°; (c) 60°