In the figure, MNPQ and NSTU are two rhombuses. If ∠STU = 108° and ∠MQP = 92°, calculate
- ∠TSU
- ∠TPN
- ∠UVP
(a)
∠TSU
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
(b)
∠TPN = ∠MQP = 92° (Corresponding angles)
(c)
∠UVP
= 92° - 36°
= 56° (Exterior angle of a triangle)
Answer(s): (a) 36°; (b) 92°; (c) 56°