In the figure, FGHJ and GLMN are two rhombuses. If ∠LMN = 121° and ∠FJH = 98°, calculate
- ∠MLN
- ∠MHG
- ∠NPH
(a)
∠MLN
= (180° - 121°) ÷ 2
= 29.5° (Isosceles triangle)
(b)
∠MHG = ∠FJH = 98° (Corresponding angles)
(c)
∠NPH
= 98° - 29.5°
= 68.5° (Exterior angle of a triangle)
Answer(s): (a) 29.5°; (b) 98°; (c) 68.5°