In the figure, DEFG and EJKL are two rhombuses. If ∠JKL = 115° and ∠DGF = 94°, calculate
- ∠KJL
- ∠KFE
- ∠LMF
(a)
∠KJL
= (180° - 115°) ÷ 2
= 32.5° (Isosceles triangle)
(b)
∠KFE = ∠DGF = 94° (Corresponding angles)
(c)
∠LMF
= 94° - 32.5°
= 61.5° (Exterior angle of a triangle)
Answer(s): (a) 32.5°; (b) 94°; (c) 61.5°