In the figure, PQRS and QUVW are two rhombuses. If ∠UVW = 115° and ∠PSR = 100°, calculate
- ∠VUW
- ∠VRQ
- ∠WXR
(a)
∠VUW
= (180° - 115°) ÷ 2
= 32.5° (Isosceles triangle)
(b)
∠VRQ = ∠PSR = 100° (Corresponding angles)
(c)
∠WXR
= 100° - 32.5°
= 67.5° (Exterior angle of a triangle)
Answer(s): (a) 32.5°; (b) 100°; (c) 67.5°