In the figure, JKLM and KPQR are two rhombuses. If ∠PQR = 117° and ∠JML = 92°, calculate
- ∠QPR
- ∠QLK
- ∠RSL
(a)
∠QPR
= (180° - 117°) ÷ 2
= 31.5° (Isosceles triangle)
(b)
∠QLK = ∠JML = 92° (Corresponding angles)
(c)
∠RSL
= 92° - 31.5°
= 60.5° (Exterior angle of a triangle)
Answer(s): (a) 31.5°; (b) 92°; (c) 60.5°