In the figure, JKLM and KPQR are two rhombuses. If ∠PQR = 122° and ∠JML = 100°, calculate
- ∠QPR
- ∠QLK
- ∠RSL
(a)
∠QPR
= (180° - 122°) ÷ 2
= 29° (Isosceles triangle)
(b)
∠QLK = ∠JML = 100° (Corresponding angles)
(c)
∠RSL
= 100° - 29°
= 71° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 100°; (c) 71°