In the figure, GHJK and HMNP are two rhombuses. If ∠MNP = 111° and ∠GKJ = 93°, calculate
- ∠NMP
- ∠NJH
- ∠PQJ
(a)
∠NMP
= (180° - 111°) ÷ 2
= 34.5° (Isosceles triangle)
(b)
∠NJH = ∠GKJ = 93° (Corresponding angles)
(c)
∠PQJ
= 93° - 34.5°
= 58.5° (Exterior angle of a triangle)
Answer(s): (a) 34.5°; (b) 93°; (c) 58.5°