In the figure, PQRS and QUVW are two rhombuses. If ∠UVW = 122° and ∠PSR = 96°, calculate
- ∠VUW
- ∠VRQ
- ∠WXR
(a)
∠VUW
= (180° - 122°) ÷ 2
= 29° (Isosceles triangle)
(b)
∠VRQ = ∠PSR = 96° (Corresponding angles)
(c)
∠WXR
= 96° - 29°
= 67° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 96°; (c) 67°