In the figure, ABCD and BFGH are two rhombuses. If ∠FGH = 116° and ∠ADC = 91°, calculate
- ∠GFH
- ∠GCB
- ∠HJC
(a)
∠GFH
= (180° - 116°) ÷ 2
= 32° (Isosceles triangle)
(b)
∠GCB = ∠ADC = 91° (Corresponding angles)
(c)
∠HJC
= 91° - 32°
= 59° (Exterior angle of a triangle)
Answer(s): (a) 32°; (b) 91°; (c) 59°