In the figure, FGHJ and GLMN are two rhombuses. If ∠LMN = 107° and ∠FJH = 97°, calculate
- ∠MLN
- ∠MHG
- ∠NPH
(a)
∠MLN
= (180° - 107°) ÷ 2
= 36.5° (Isosceles triangle)
(b)
∠MHG = ∠FJH = 97° (Corresponding angles)
(c)
∠NPH
= 97° - 36.5°
= 60.5° (Exterior angle of a triangle)
Answer(s): (a) 36.5°; (b) 97°; (c) 60.5°