In the figure, GHJK and HMNP are two rhombuses. If ∠MNP = 124° and ∠GKJ = 96°, calculate
- ∠NMP
- ∠NJH
- ∠PQJ
(a)
∠NMP
= (180° - 124°) ÷ 2
= 28° (Isosceles triangle)
(b)
∠NJH = ∠GKJ = 96° (Corresponding angles)
(c)
∠PQJ
= 96° - 28°
= 68° (Exterior angle of a triangle)
Answer(s): (a) 28°; (b) 96°; (c) 68°