In the figure, FGHJ and GLMN are two rhombuses. If ∠LMN = 110° and ∠FJH = 96°, calculate
- ∠MLN
- ∠MHG
- ∠NPH
(a)
∠MLN
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
(b)
∠MHG = ∠FJH = 96° (Corresponding angles)
(c)
∠NPH
= 96° - 35°
= 61° (Exterior angle of a triangle)
Answer(s): (a) 35°; (b) 96°; (c) 61°