In the figure, MNPQ and NSTU are two rhombuses. If ∠STU = 121° and ∠MQP = 97°, calculate
- ∠TSU
- ∠TPN
- ∠UVP
(a)
∠TSU
= (180° - 121°) ÷ 2
= 29.5° (Isosceles triangle)
(b)
∠TPN = ∠MQP = 97° (Corresponding angles)
(c)
∠UVP
= 97° - 29.5°
= 67.5° (Exterior angle of a triangle)
Answer(s): (a) 29.5°; (b) 97°; (c) 67.5°