In the figure, GHJK and HMNP are two rhombuses. If ∠MNP = 120° and ∠GKJ = 100°, calculate
- ∠NMP
- ∠NJH
- ∠PQJ
(a)
∠NMP
= (180° - 120°) ÷ 2
= 30° (Isosceles triangle)
(b)
∠NJH = ∠GKJ = 100° (Corresponding angles)
(c)
∠PQJ
= 100° - 30°
= 70° (Exterior angle of a triangle)
Answer(s): (a) 30°; (b) 100°; (c) 70°