In the figure, GHJK and HMNP are two rhombuses. If ∠MNP = 106° and ∠GKJ = 97°, calculate
- ∠NMP
- ∠NJH
- ∠PQJ
(a)
∠NMP
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
(b)
∠NJH = ∠GKJ = 97° (Corresponding angles)
(c)
∠PQJ
= 97° - 37°
= 60° (Exterior angle of a triangle)
Answer(s): (a) 37°; (b) 97°; (c) 60°