In the figure, DEFG and EJKL are two rhombuses. If ∠JKL = 113° and ∠DGF = 97°, calculate
- ∠KJL
- ∠KFE
- ∠LMF
(a)
∠KJL
= (180° - 113°) ÷ 2
= 33.5° (Isosceles triangle)
(b)
∠KFE = ∠DGF = 97° (Corresponding angles)
(c)
∠LMF
= 97° - 33.5°
= 63.5° (Exterior angle of a triangle)
Answer(s): (a) 33.5°; (b) 97°; (c) 63.5°