In the figure, PQRS and QUVW are two rhombuses. If ∠UVW = 117° and ∠PSR = 101°, calculate
- ∠VUW
- ∠VRQ
- ∠WXR
(a)
∠VUW
= (180° - 117°) ÷ 2
= 31.5° (Isosceles triangle)
(b)
∠VRQ = ∠PSR = 101° (Corresponding angles)
(c)
∠WXR
= 101° - 31.5°
= 69.5° (Exterior angle of a triangle)
Answer(s): (a) 31.5°; (b) 101°; (c) 69.5°