In the figure, FGHJ and GLMN are two rhombuses. If ∠LMN = 120° and ∠FJH = 94°, calculate
- ∠MLN
- ∠MHG
- ∠NPH
(a)
∠MLN
= (180° - 120°) ÷ 2
= 30° (Isosceles triangle)
(b)
∠MHG = ∠FJH = 94° (Corresponding angles)
(c)
∠NPH
= 94° - 30°
= 64° (Exterior angle of a triangle)
Answer(s): (a) 30°; (b) 94°; (c) 64°