In the figure, FGHJ and GLMN are two rhombuses. If ∠LMN = 107° and ∠FJH = 95°, calculate
- ∠MLN
- ∠MHG
- ∠NPH
(a)
∠MLN
= (180° - 107°) ÷ 2
= 36.5° (Isosceles triangle)
(b)
∠MHG = ∠FJH = 95° (Corresponding angles)
(c)
∠NPH
= 95° - 36.5°
= 58.5° (Exterior angle of a triangle)
Answer(s): (a) 36.5°; (b) 95°; (c) 58.5°