In the figure, DEFG and EJKL are two rhombuses. If ∠JKL = 107° and ∠DGF = 95°, calculate
- ∠KJL
- ∠KFE
- ∠LMF
(a)
∠KJL
= (180° - 107°) ÷ 2
= 36.5° (Isosceles triangle)
(b)
∠KFE = ∠DGF = 95° (Corresponding angles)
(c)
∠LMF
= 95° - 36.5°
= 58.5° (Exterior angle of a triangle)
Answer(s): (a) 36.5°; (b) 95°; (c) 58.5°