In the figure, JKLM and KPQR are two rhombuses. If ∠PQR = 109° and ∠JML = 98°, calculate
- ∠QPR
- ∠QLK
- ∠RSL
(a)
∠QPR
= (180° - 109°) ÷ 2
= 35.5° (Isosceles triangle)
(b)
∠QLK = ∠JML = 98° (Corresponding angles)
(c)
∠RSL
= 98° - 35.5°
= 62.5° (Exterior angle of a triangle)
Answer(s): (a) 35.5°; (b) 98°; (c) 62.5°